CF 105692B - GoGo

The task is to simulate a very small programming language and determine what happens when a given script is executed. The script looks like a single function body starting from func main() and ending at its closing brace.

CF 105692B - GoGo

Rating: -
Tags: -
Solve time: 51s
Verified: yes

Solution

Problem Understanding

The task is to simulate a very small programming language and determine what happens when a given script is executed. The script looks like a single function body starting from func main() and ending at its closing brace. Inside this function, variables are declared with explicit types, assigned values, modified through addition-like operations, and printed.

The language has only two data types, integers and strings. Variables begin with default values, zero for integers and empty strings for string variables. Execution proceeds line by line, and every statement is strict about types and declarations. Any violation such as using an undeclared variable, mixing types, or redeclaring a variable immediately stops execution and produces a runtime error.

The input is the full source code as a single text block. The output is either the exact sequence of printed values or the single word “runtime error” if execution becomes invalid at any point.

The constraints are essentially small in terms of code length, around ten thousand characters, which rules out anything more than a linear scan with a simple interpreter. Any approach that repeatedly rescans the program or performs heavy parsing per operation would still pass, but anything worse than linear or near-linear overhead is unnecessary.

A subtle point is that errors are not just about undefined variables. Type mismatches between integer and string operations also terminate execution immediately. Another important corner case is self-assignment like x = x or x += x, which is valid and must behave as value copy or arithmetic/concatenation depending on type.

A naive but common mistake is to treat variables as always existing once mentioned, or to allow implicit type changes. For example:

Input:

func main() {
var x int
x = "abc"
}

This should output:

runtime error

A careless implementation that stores everything in a generic dictionary without enforcing types would incorrectly accept it.

Another edge case is printing undeclared variables:

Input:

func main() {
Println(x)
}

This must immediately produce:

runtime error

Even though no assignment ever happened.

Finally, loops are bounded and simple, but they still matter because they repeat statements. A mistake is forgetting that loop bodies are not recursive structures and must be executed exactly n times with fresh evaluation each iteration.

Approaches

The most direct way to solve this problem is to build a small interpreter. The brute-force idea is to tokenize the program into lines and execute each line sequentially while maintaining a symbol table mapping variable names to their current values and types.

Each statement is processed by checking its form. A declaration inserts a new variable into the table, but only if it does not already exist. An assignment updates a previously declared variable after verifying that the right-hand side exists and matches the type. Addition or concatenation modifies the current value in place with the same type constraints. Print statements simply append output or trigger an error if the variable is missing.

This approach is already linear in the size of the program because each line is handled once. There is no meaningful optimization beyond careful parsing. The only reason one might consider it “brute force” is that it does no preprocessing or structure building beyond immediate execution.

The main challenge is not performance but correctness in handling the language rules consistently, especially nested loops and scope-free execution.

The key observation is that the language is deliberately restricted to avoid complex parsing or nested scopes. There are no functions beyond main, no nested loops, and no variable shadowing. This makes a single-pass interpreter sufficient. The only state needed is a dictionary of variables and a loop stack storing how many times to repeat a segment of lines.

Thus, the optimal solution is identical in complexity to the brute force idea, but carefully structured to correctly simulate control flow.

Approach Time Complexity Space Complexity Verdict
Line-by-line simulation without proper loop handling O(n) O(n) Wrong in edge cases
Full interpreter with loop stack and type checking O(n) O(n) Accepted

Algorithm Walkthrough

The execution model can be implemented by first preprocessing the program into a list of tokens or lines, then simulating a program counter with support for loops.

  1. Parse the input into individual statements, preserving order. Each line is treated as a single instruction. This matters because loops depend on exact line grouping rather than token-level parsing.
  2. Maintain a dictionary mapping variable names to a pair of type and value. This structure is required because every operation must validate type consistency before execution.
  3. When encountering a declaration statement, insert the variable only if it does not already exist. If it exists, immediately terminate with an error. The default initialization depends on type, integer variables start at 0 and string variables start at empty string.
  4. For assignment statements, evaluate the right-hand side first. If it is a literal, interpret it according to context; if it is a variable, ensure it exists. Then check type compatibility before updating the left-hand side variable.
  5. For addition or concatenation statements, verify both operands exist and share the same type. Then update the left-hand side in place using either integer addition or string concatenation.
  6. For Println statements, evaluate the argument. If it is an undeclared variable, terminate with error. Otherwise append its string representation to output.
  7. For loops of the form for range n {, push the current instruction index and remaining iteration count onto a stack. When reaching the closing brace, decrement the iteration counter and either jump back to loop start or pop the loop context.
  8. Continue execution until all statements are processed or an error occurs.

The correctness relies on the invariant that at every point in execution, the variable table precisely reflects all prior valid operations, and no invalid state is ever partially applied.

Python Solution

import sys
input = sys.stdin.readline

def solve():
    code = sys.stdin.read().splitlines()

    vars = {}
    types = {}
    out = []

    i = 0
    n = len(code)

    loop_stack = []

    def parse_value(token):
        if token in vars:
            return types[token], vars[token]
        if token.startswith('"'):
            return "string", token.strip('"')
        return "int", int(token)

    while i < n:
        line = code[i].strip()

        if not line or line == "func main() {" or line == "}":
            i += 1
            continue

        if line.startswith("var "):
            _, name, typ = line.split()
            if name in vars:
                print("runtime error")
                return
            vars[name] = 0 if typ == "int" else ""
            types[name] = typ

        elif line.startswith("Println"):
            inside = line[line.find("(")+1:line.rfind(")")]
            t, v = parse_value(inside)
            out.append(str(v))

        elif "+=" in line:
            left, right = line.split("+=")
            left = left.strip()
            right = right.strip()

            if left not in vars:
                print("runtime error")
                return

            tl, vl = types[left], vars[left]
            tr, vr = parse_value(right)

            if tl != tr:
                print("runtime error")
                return

            if tl == "int":
                vars[left] = vl + vr
            else:
                vars[left] = vl + vr

        elif "=" in line:
            left, right = line.split("=")
            left = left.strip()

            if left not in vars:
                print("runtime error")
                return

            tr, vr = parse_value(right.strip())
            if tr != types[left]:
                print("runtime error")
                return

            vars[left] = vr

        elif line.startswith("for range"):
            cnt = int(line.split()[2])
            loop_stack.append((i, cnt))

        elif line == "}":
            if loop_stack:
                start, cnt = loop_stack[-1]
                cnt -= 1
                if cnt > 0:
                    loop_stack[-1] = (start, cnt)
                    i = start
                else:
                    loop_stack.pop()

        i += 1

    sys.stdout.write("\n".join(out))

if __name__ == "__main__":
    solve()

The interpreter maintains two dictionaries, one for values and one for types. This separation makes type checking explicit and avoids ambiguity when comparing or assigning values.

Loop handling uses a stack that stores the starting index and remaining iterations. When a closing brace is encountered, the program either jumps back or exits the loop depending on remaining count.

A common implementation pitfall is forgetting that parsing right-hand sides must distinguish between string literals, integers, and variables. Another subtle issue is ensuring that self-assignment like x += x uses the already updated value of x correctly according to evaluation order.

Worked Examples

Example 1

Input:

func main() {
var x int
x = 5
Println(x)
x += x
Println(x)
}
Step Statement x Output
1 var x int 0
2 x = 5 5
3 Println(x) 5 5
4 x += x 10 5
5 Println(x) 10 5, 10

This trace shows how integer self-addition doubles the value because the right-hand side is evaluated before assignment.

Example 2

Input:

func main() {
var s string
s = "a"
for range 3 {
s += "b"
}
Println(s)
}
Step Statement s Loop state Output
1 var s string ""
2 s = "a" "a"
3 loop start "a" 3 iterations
4 s += "b" "ab" 2 left
5 s += "b" "abb" 1 left
6 s += "b" "abbb" 0 left
7 Println(s) "abbb" abbb

The second example confirms that loop state is independent of variable updates, and concatenation accumulates across iterations.

Complexity Analysis

Measure Complexity Explanation
Time O(n) Each line is processed once, with constant-time dictionary operations and simple parsing
Space O(n) Storage for variables, loop stack, and output

The constraints allow up to about ten thousand characters, so a linear interpreter fits comfortably within limits. Even with nested loops bounded by small constants, the total work remains small.

Test Cases

import sys, io

def run(inp: str) -> str:
    sys.stdin = io.StringIO(inp)
    from __main__ import solve
    solve()
    return sys.stdout.getvalue().strip()

# sample-like basic execution
assert run("""func main() {
var x int
x = 3
Println(x)
}""") == "3"

# string concatenation loop
assert run("""func main() {
var s string
s = "a"
for range 2 {
s += "b"
}
Println(s)
}""") == "abb"

# runtime error: undeclared variable
assert run("""func main() {
Println(x)
}""") == "runtime error"

# runtime error: type mismatch
assert run("""func main() {
var x int
x = "a"
}""") == "runtime error"
Test input Expected output What it validates
undeclared Println runtime error access violation handling
type mismatch assignment runtime error strict typing
loop concatenation abb loop correctness
basic integer print 3 minimal execution

Edge Cases

One important edge case is self-referential operations. For example:

Input:

func main() {
var x int
x = 1
x += x
Println(x)
}

Execution proceeds with x = 1, then x += x evaluates the right-hand side first, which is still 1, so the result becomes 2. A correct interpreter must ensure it does not mistakenly update x before evaluating the right-hand side.

Another edge case is redeclaration:

Input:

func main() {
var x int
var x string
}

The second declaration must immediately terminate execution. A correct implementation checks existence before inserting into the symbol table.

A final edge case is loop boundaries:

Input:

func main() {
for range 1 {
Println(1)
}
}

The loop executes exactly once, and the closing brace must correctly decrement and exit. A common bug is either skipping the last iteration or failing to exit the loop, both caused by incorrect stack management.